Shocking Current

Electricity and Magnetism Level 2

In a neon discharge tube 2.8 × 1 0 18 N e X + 2.8 × 10^{18} \ \ce{Ne+} ions move to the right per second while 1.2 × 1 0 18 1.2 ×10^{18} electrons move to the left per second. What is the current in the discharge tube?

Source: NSEJS

0.64 A towards left 0.256 A towards left 6.4 A towards right 0.64 A towards right 0.256 A towards right

Anurag Bisht by Anurag Bisht , 17, India

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1 solution

Anurag Bisht
Sep 4, 2017

As current is considered as the flow of positive charge so, net flow of charge towards right or net flow of positive charge = ne. As I = ne/t, here t = 1 .So, I = (1.2+ 2.8)×10^18 ×1.6 × 10^–19 A= 0.64 A (towards right)

0 Helpful 0 Interesting 0 Brilliant 0 Confused

@Anurag Bisht even i could solve this,what 's so shocking in it ?? and btw I = d Q d t I = \frac{dQ}{dt} for more general form.

Ayon Ghosh - 3 years, 9 months ago

and please write in latex its hard to read otherwise.

Ayon Ghosh - 3 years, 9 months ago

@Ayon Ghosh I solved it bro just for a good name I chose it . You want more questions.....wait 1 week

Anurag Bisht - 3 years, 9 months ago

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