Shooting Zone 2

We can solve this by Combinatorics, Programming or just by taking numbers of our choice and observing the pattern etc.

The pattern we get here is simple but "interesting". If the given no. of people are X .

we find a number ${2}^{N} \le X$ ( where N is any whole number )

Find the difference D between them,

$D={X} - {2}^{N}$

Then the difference D will give us the answer A ,

if ${D}=0$ , then $0\equiv1$ and $A=1$

if ${D}=1$ , then $1\equiv3$ and $A=3$

if ${D}=2$ , then $2\equiv5$ and $A=5$

$\therefore A=2D+1$

So this is the pattern which we will get.

Exempli gratia

Here $X=10000$ . The closest no. of form $2^N$ is $2^{13}=8192$ .

Difference $D=1808$ .

So, Answer is $2D + 1$ i.e. $2\times1808 +1 = 3617$ .

For Shooting Zone 1 $X=100$

$100-2^6=36$ . $A=2\times36 +1$

$\therefore A=73$

$:)$