Short and sweet

A particle moves along a parabolic path x = y 2 + 2 y + 2 x=y^2+2y+2 in such a way that the y-component of velocity vector remains 5 m/s 5 \text{ m/s} durin the motion. The magnitude of the acceleration of the particle is 10 X m/s 2 10X \text{ m/s}^2 . Find the value of X.


The answer is 5.

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