Shortest Distance from Circle to Parabola (Part 2)

Geometry Level 5

In the x y z xyz coordinate system, there is a circle with the following properties:

Center: C = ( 0 , 0 , 2 ) \vec{C} = (0,0,2)
Normal Vector to Plane Containing Circle: N = ( 1 , 1 , 1 ) \vec{N} = (1,1,1)
Radius: R = 5 R = 5

The is also a parabola with the following parametrization:

P = α u 1 + α 2 u 2 \large{\vec{P} = \alpha \, \vec{u_1} + \alpha^2 \, \vec{u_2}}

In the above expression, u 1 \vec{u_1} is a unit-vector in the direction of ( 1 , 2 , 3 ) (-1,2,3) and u 2 \vec{u_2} is a unit-vector in the direction of ( 2 , 5 , 4 ) (2,-5,4) . The variable α \alpha is a spatial parameter.

What is the minimum distance from the circle to the parabola?


The answer is 0.895.

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