Shortest Path On a Cylinder

Geometry Level 2

A cylinder has its axis extending along the z z axis, with a radius of 10 10 . Two points are on the surface of this cylinder which are A ( 10 , 0 , 0 ) A (10, 0, 0) and B ( 10 , 0 , 10 ) B (-10, 0, 10) . What is the length of the shortest path from A A to B B such that the path lies entirely on the surface of the cylinder ?


The answer is 32.969.

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1 solution

Henry U
Jan 18, 2019

Consider cutting the cylinder along the two lines x = 10 , y = 0 x=10,y=0 and x = 10 , y = 0 x=-10,y=0 . You get two rectangles, each with side lengths of 10 10 and 1 2 2 π 10 = 10 π \frac 12 2 \pi \cdot 10 = 10\pi .

The points we want to connect lie on two opposite corners of these rectangles, so the shortest path between them is one rectangle's diagonal, which has a length of

( 10 ) 2 + ( 10 π ) 2 = 10 1 + π 2 32.969 \sqrt{(10)^2+(10\pi)^2} = 10\sqrt{1+\pi^2} \approx \boxed{32.969} .

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