Shot Is fired...
Classical Mechanics
Level
3
A shot is fired from a point at a distance of 200
m
from the foot of a tower 100
m
high so that the bullet just passes over the tower. What is the direction of the shot?
70 degree
30 degree
45 degree
60 degree
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1 solution
x=200\quad m\ x=\frac { { V } { 0 }^{ \quad \quad 2 }\quad \sin { \theta \quad cos\theta } }{ g } \ 200\quad =\quad \frac { { V } { o }^{ \quad 2 }\quad sin\theta \quad cos\theta }{ g } \ \frac { 200 }{ cos\theta } =\frac { { V }_{ 0 }^{ \quad 2 }\quad sin\theta }{ g } \quad ...........(1)\ \ Substitute\quad (1)\quad to\quad (2)\ \ y=100\quad m