Should have done this 6 years back!

Algebra Level 4

Let P ( x ) P(x) be a polynomial with degree 2009 and leading co-efficient unity such that

P ( 0 ) = 2008 , P ( 1 ) = 2007 , P ( 2 ) = 2006 , . . . . . . . . , P ( 2008 ) = 0 P ( 0 ) = 2008, P ( 1 ) = 2007, P ( 2 ) = 2006, . . . . . . . . , P ( 2008 ) = 0

and the value of P ( 2009 ) = ( n ! ) a P(2009) = (n!) - a where n n and a a are natural numbers, then the value of n + a n+a is ?

Try my set


The answer is 2010.

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1 solution

Just consider the polynomial P(n) + n -2008 . This has roots 0 to 2008. Rest is trivial.

The polynomial?

Vishwak Srinivasan - 6 years, 1 month ago

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