Should I plot them? 2

Calculus Level 3

A straight line is to be drawn through a point whose coordinates are ( x , y ) = ( 2 , 1 ) (x,y)=(2,-1) as tangent to the curve y = x 2 5 x + 6 y=x^2-5x+6 . Let the coordinates of the points where the line is tangent to the curve be ( x 1 , y 1 ) (x_1,y_1) and ( x 2 , y 2 ) (x_2,y_2) .

Find x 1 + y 1 + x 2 + y 2 x_1+y_1+x_2+y_2 .


The answer is 6.

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2 solutions

Akshay Yadav
Mar 31, 2016

Both the questions in series 'Should I plot them?' have been taken from Calculus Made Easy by Silvanus P. Thompson. Both of them are interesting questions indeed.

First of all we consider the points A ( x 1 , y 1 ) A(x_1,y_1) and B ( x 2 , y 2 ) B(x_2,y_2) as tangency points on the curve y = x 2 5 x + 6 y=x^2-5x+6 . It is self evident at these points the slope of tangents passing through ( 2 , 1 ) (-2,1) must be equal to that of curve.

Let the equation of tangent line be y = m x + c y=mx+c (we will consider only one line here). Clearly ' m m ' is the slope of line.

Slope of the curve d y d x = 2 x 5 \frac{dy}{dx}= 2x-5 ,

So,

m = 2 x 5 m=2x-5

Also,

The the equation must satisfy ( 2 , 1 ) (2,-1) , so 1 = 2 m + c -1=2m+c or c = 2 m 1 c=-2m-1

Now solving for points A A and B B by equating the equation of tangent line to that of the curve.

x 2 5 x + 6 = ( 2 x 5 ) x ( 2 x 5 ) 1 x^2-5x+6=(2x-5)x-(2x-5)-1

x 2 4 x + 3 = 0 x^2-4x+3=0

x = x 1 = 3 x=x_1=3 or x = x 2 = 1 x=x_2=1

So,

A ( 3 , 0 ) A(3,0) and B ( 1 , 2 ) B(1,2)

Recheck your solution. Some line(s) contain typos which makes it misleading.

A Former Brilliant Member - 3 years, 5 months ago
Hobart Pao
Apr 2, 2016

(not a solution.) @Brian Charlesworth

The given solution is correct, I think.

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