Sick square 2
Geometry
Level
1
Each side of the square ABCD has length 1.
With angle PAQ given, find the Perimeter of the triangle QPC.
The answer is 2.
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1 solution
Also
Angle DAQ= Angle B'AP'
and angle
DAQ + PAB = B'AP' + DAQ' = 45
so angle Q'AQ = 45
Triangle Q'AQ is congruent to triangle AQP and AQ'P'
length QQ' = PQ
and PC = C'Q'
perimeter triangle QPC= C'C = 2