cos x ⎝ ⎛ sin x + sin 2 x + 4 3 ⎠ ⎞
Find the maximum value of the expression above, where x ∈ R .
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Thanks for posting a solution!
Hint : When all fails, Cauchy Schwartz hails~!
(Though we can solve this problem without Cauchy Schwartz also but that would be too lengthy/)
Nice statement.Although I solved by a quadratic m a x √ ( 1 / 4 ) ( − x 2 + 1 1 / 2 x − 9 / 1 6 ) .This wasn't much lengthy though.Max value is √ ( 7 / 2 ) .my app was set S i n x + √ ( s i n 2 x + 3 / 4 ) = y yields ( y 2 − 3 / 4 ) / 2 y = s i n x .Now we need to max y c o s x .so square it and express c o s in terms of s i n gives us to maximise a quadratic.
Quite creative.
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Thanks for the advice from Harsh Shrivastava , the solution is as follows:
By Cauchy-Schwarz inequality:
( sin x cos x + cos x sin 2 x + 4 3 ) 2 ⟹ cos x ( sin x + sin 2 x + 4 3 ) ≤ ( sin 2 x + cos 2 x ) ( cos 2 x + sin 2 x + 4 3 ) = ( 1 ) ( 1 + 4 3 ) = 4 7 ≤ 2 7 ≈ 1 . 3 2 3