Distance to the horizon

Geometry Level 1

Two communication satellites are in Earth's orbit at altitudes of 96 miles and 137 miles, respectively.

If a signal must be sent between them in a straight line without Earth obstructing it, what is the maximum distance (in miles) that the satellites can be from each other?

Round your answer to the nearest hundred. Assume that Earth is a perfect sphere and that its radius is 4000 miles.

900 1700 1900 2100

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4 solutions

Doubt clear, thank for answering.🤓

Ravi Rajbhar - 2 years, 7 months ago
Alan Astbury
Nov 2, 2018

The Greatest distance occurs when the line connecting the satellites is tangential to the outline of the earth.

Consider the following Model

Given that this line will be Tangential, it will intersect the Circle at the point P, and the angle between the radius and this tangent shall be a right angle (by Circle Theorem) and P shall have a distance from C of 4000 as it lies on the circle.

This forms 2 distinct right triangles (CPS1 and CPS2) of which 2 lengths are known.

The triangle formed by Satellite 1 (S1), has a hypotenuse length of 4096 as S1 is 96 Miles above the surface of the earth.

Likewise, the triangle formed by Satellite 2 (S2), has a Hypotenuse of 4137 as S2 is 137 Miles above the surface of the earth. . Using Pythagoras' Theorem, we get PS1 being 881.6 and PS2 being 1055.82.

881.6 + 1055.82 = 1937.42.

Closest answer is 1900.

Thank you for posting a nice solution!

A Former Brilliant Member - 2 years, 7 months ago

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Thank you for a great question!

Alan Astbury - 2 years, 7 months ago

import math x = math.sqrt(8137 137) + math.sqrt(8096 96) print(x)

Run that by me again. I think something got lost in translation.

Robert Kelleher - 2 years, 7 months ago

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it is a little bit gap between the accurate solution,may be python not support?

丁大喵 by丁丁猫 - 2 years, 7 months ago
Elias Cotton
Nov 4, 2018

4096×(sin(cos⁻¹(4000÷4096))) + 4137×(sin(cos⁻¹(4000÷4137))) Just using trig instead of Pythagoras because it's too early in the morning.

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