Sigma with pi

Algebra Level 1

$\dfrac{\displaystyle\sum_{n=2}^5 n }{\displaystyle\prod_{k=1}^3 k } = \, ?$

\frac{14}{5}

\frac{7}{3}

\frac{7}{8}

\frac{13}{6}

3 solutions

Sudoku Subbu
Jan 17, 2015

consider the numerator ==> 2+3+4+5 = 14 consider the denominator ===> 1X2X3 = 6 \frac{numerator}{denominator} = \frac{14}{6} = \frac{7}{3}

Nikhil Raj
May 30, 2017

ANSWER = $\displaystyle \dfrac{\sum_{n=2}^5n}{\prod_{k=1}^3k} = \dfrac{2 + 3 + 4 + 5}{1 \times 2 \times 3} = \dfrac{14}6 = \boxed{\dfrac{7}{3}}$

Nelson Mandela
Jan 16, 2015

So sigma is sum and pi is product.

We have sigma (n=2 to 5) n = 2+3+4+5 = 14.

We also have pi (k = 1 to 3) n = 1x2x3 = 6.

So the answer is 14/6 = 7/3.