Silas's bills

$(4 \times 1)+(3 \times 5)+(2 \times 10)+(1 \times 20)$

$4+15+20+20$

$=59$

(1x4)+(5x3)+(10x2)+(20x1)=59

x=4(1)+3(5)+2(10)+1(20) x=59

4x1+3x5+2x10+1x20=59

4x1 + 3x5 + 2x10 + 1x20 = 4 + 15 + 20 + 20 = 59

We have 4x1=4, 3x5=15, 2x10 =20 and 20x1 =20. Sum = 4+15+20+20=59

4x1=4 3x5=15 2x10=20 1x20=20 4+15+20+20=59

here 10 bills in Silas' wallet . Money= $[(4 1)+(3 5)+2(10)+1(20)] Money = $59

(4×1)+(3×5)+(2×10)+(1×20)

4+15+20+20

(1x4)+(5x3)+(10x2)+(20x1)= 4+15+20+20=59

4 1+3 5+2 10+1 20=4+15+20+20=59

59

4+15+20+20=59

total money=Summation x * y where x=number of bills y=dollars

we have the money described in the question. 4$1 bills=4X1=4 3$5 bills=3X5=15 2$10 bills=2X10=20 1$20 bills=1X20=20 now add up all these the answer wll come $59.

59

Total money in the wallet od Silas is : T=4+3 5+2 10+20=59

Multiply the amount by quantity.

(4x1)+(3x5)+(2x10)+(1x20)=59

4(1)+3(5)+2(10)+1(20)=59 Hence, 59 $

(1x4)+(5x3)+(10x2)+(20x1)=59

( 4 X $1) + ( 3 X $5 ) + (2 X $10) + (1 X $20) = (4 $) +(15 $)+(20 $)+(20 $) = 59 $

(4×1)+(3×5)+(2×10)+(1×20)= 4+15+20+20 =59

4 times $1 Bills, which mean = $4, 3 times $5 Bills which mean = $15, 2 times $10 Bills which mean =$20, and 1 times $20 Bills which mean = $20, now >>> $4 + $15 +$20 + $20 = $59, easy isn't? its way for you guide by Logic, I'm a social man...

(1x4)+(5x3)+(10x2)+(20x1)=59

=(4x1)+(3x5)+(2x10)+(1x20) =4+15+20+20 =59

4+15+20+20=59

(1x4)+(5x3)+(10x2)+(20x1) 4+15+20+20 =59

(Do the equation within the bracket first.)

4+15+20+20=59

4X1=4 3X5=15 2X10=20 1X20=20 *4+15+20+20=59

4 x 1=4 3 x 5=15 2 x 10=20 1 x 20=20 59