Silver Medal Possibilities

There are $7$ medals ( $11 - 4$ ) that could have been bronze or silver.

Thus, Norway could have won $0,1,2,3,4,5,6$ or $7$ medals. That means there are $\boxed{8}$ different possibilities.

The number of silver medals can be any number between 0 and 7 as 7+4=11 (the total tally).

( Bronze medalls will fill up the remaining places so as to make the total 11 even when 7 silver medals are not won )

So number of possibilities = $\boxed{8}$ .

$11-4+1=\boxed{8}$

First we must determine how many Silver or Bronze medals Norway has. We do this by subtracting the 4 gold medals they won from their total medal count of 11. This shows us that they have won 7 Silver or Bronze medals. We can then see that Silver medals could have a value between 0-7 and this shows that there are 8 possibilities of the Silver medal count. Notes: "0" is counted as a possibility because it is possible that no Silver medals were won and that all 7 medals were Bronze.

if there are 4 gold medals that means that there are 7 more medals either silver or bronze so there could be : 0 bronze 7 silver, 1 bronze 6 silver, 2 bronze 5 silver, 3 bronze 4 silver, 4 bronze 3 silver, 5 bronze 2 silver, 6 bronze 1 silver, and 7 bronze and 0 silver (don't forget that there could be 0 silvers)
when you count them it equals 8

There could be any number of silver medals from 0 through 7, bringing the count of possibilities at 8.

Total no. of medals =11

No. of gold medals = 4

Remaining medals = 7

Suppose :- 1) All 7 medals are silver. 2) Not at all 7 medals are silver , they all are bronze.

So, first there are 7 possibilities that all medals are silver and 1 possibility that there is no 1 silver medal they had , all are bronze.

So total no. of possibilities = 7+1=8

There are 4 gold medals, so 7 medals are either bronze, silver or both. You can easily count it just by counting down from 7 - 7 medals, 6 medals, 5 medals, 4 medals, 3 medals, 2 medals, one medal, and 0 medals. Therefore there are 8 possibilities.

4*2=8

they have chance to get either 0 or 1 or 2 or 3 or 4 or 5 or 6 or 7 silver medals ;total 8 possibilities

8

total of 11 medals 4 gold, which implies remaining medals= 7 now possible situation: 0 silver, 7 bronze; 1 silver, 2 silver, 3 silver, 4 silver, 5 silver, 6 silver and 7 silver, 0 bronze therefore a total of 8 different possibilities

they have 8 case, 0,1,2,3,4,5,6,7

as there are 3 types of medals Gold Silver & Bronze and we already know that they are with 4 Gold out of 11 medals they won and the remaining medals unknown can be in this form with 8 ways ( 0 S-8 B , 1 S=7 B , 2 S-6 B , 3 S-5B , 4 S-4 B , 5 S-3 B , 6 S-2 B , 7 S-1 B , 8 S- 0 B ) ,so the answer is 8 ways

So the other seven medals can be either silver or bronze. Thus they have all the possibilities of getting silver medals from 0 to 7. So there are totally 8 different possibilities of number of silver medals

n - number of medals available (7 = 11-4) r - number of of ways it can be won (2 = either silver or bronze) we can do an analogy of this problem to a more common probability related question, in how many ways can 'n' items be distributed into 'r' container and each container may have zero or more items. The answer is: n+r-1C r-1 : 7+2-1 C 2-1 = 8

You either have no silver and 7 bronze (since we only have 11 - 4 medals) or 1 silver and 6 bronzes or 2 silvers and 5 bronzes or 3 silvers and 4 bronzes or 4 silvers and 3 bronzes or 5 silvers and 2 bronzes or 6 silvers and 1 bronze or 7 silvers and 0 bronze. All in all we have 8 different possibilities.

Either 0,1,2,3,4,5,6,7.

Norway was leading with $11$ medals out of which there are $4$ gold medals. So, there are $(11-4)=7$ bronze or silver medals. Now, out of these medals, there are $8$ possibilities of getting silver medals. They can have $0$ to $7$ silver medals out of the $7$ remaining medals. Thus, we have a total of 8 possibilites on the number of silver medals that they might have had.

So, the answer is $=\boxed{8}$

there are 8 possibilities in total i.e. no. of SILVER & BRONZE medals 0 8 1 7 .. ... 6 1 7 0