If a is a real number such that a + a 1 = 5 , find the value of a 2 + a 2 1 .
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When you squared the equation, where did the +2 come from?
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Remember that
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simple square both sides and subtract 2 from the value... we get 25-2 = 23
a^2+(1/a)^2=(a+1/a)^2-2 a 1/a=(5)^2-2=25-2=23
Wouldn't a better solution be squaring a + 1/a=5 then deriving at a^2+2+1/a^2=25? Hence, the answer would be 23 as a^2+1/a^2=25-2.
(a + 1/a )^2 = 25
(a^2) + 2 + (1/a)^2 = 25
(a^2) + (1/a)^2 = 23
Note that
( a + a 1 ) 2 = a 2 + a 2 1 + 2
Hence,
a 2 + a 2 1 = 2 5 − 2 = 2 3 ,
and we are done.
I just ended up with trial and error, ending up with a as 4 . 7 5 .
4 . 7 5 + 4 . 7 5 1 = 4 . 9 6 0 5 2 6 3 1 5 7 8 . . . which estimates to 5
4 . 7 5 2 = 2 2 . 5 6 2 5
2 2 . 5 6 2 5 + 2 2 . 5 6 2 5 1 = 2 2 . 6 0 6 8 2 1 3 2 9 6 . . . which estimates to 2 3
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We simply square the expression: ( a + a 1 ) 2 = 5 2 ⟹ a 2 + 2 + a 2 1 = 2 5 ⟹ a 2 + a 2 1 = 2 3