Simple

Algebra Level 2

If a a is a real number such that a + 1 a = 5 a+\frac{1}{a}=5 , find the value of a 2 + 1 a 2 a^2+\frac{1}{a^2} .


The answer is 23.

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7 solutions

Zarak K
Aug 23, 2014

We simply square the expression: ( a + 1 a ) 2 = 5 2 a 2 + 2 + 1 a 2 = 25 a 2 + 1 a 2 = 23 (a + \frac{1}{a})^2 = 5^2 \\ \implies a^2 + 2 + \frac{1}{a^2} = 25 \\ \implies a^2 + \frac{1}{a^2} = 23

When you squared the equation, where did the +2 come from?

Jason Suited - 6 years, 9 months ago

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Remember that ( a + b ) 2 = a 2 + 2 a b + b 2 (a + b)^2 = a^2 + 2ab+b^2
So ( a + 1 a ) 2 = a 2 + 2 ( a × 1 a ) + ( 1 a ) 2 = a 2 + 2 + 1 a 2 (a+\frac{1}{a})^2=a^2+2(a \times \frac{1}{a}) +(\frac{1}{a})^2 = a^2 + 2 + \frac{1}{a^2}

Trí Onii-sama - 6 years, 7 months ago
Ritam Baidya
Dec 3, 2014

simple square both sides and subtract 2 from the value... we get 25-2 = 23

Rifath Rahman
Aug 27, 2014

a^2+(1/a)^2=(a+1/a)^2-2 a 1/a=(5)^2-2=25-2=23

Tan Yong Boon
Aug 23, 2014

Wouldn't a better solution be squaring a + 1/a=5 then deriving at a^2+2+1/a^2=25? Hence, the answer would be 23 as a^2+1/a^2=25-2.

Eslam Samy
Aug 23, 2014

(a + 1/a )^2 = 25

(a^2) + 2 + (1/a)^2 = 25

(a^2) + (1/a)^2 = 23

Victor Loh
Aug 23, 2014

Note that

( a + 1 a ) 2 = a 2 + 1 a 2 + 2 (a+\frac{1}{a})^2=a^2+\frac{1}{a^2}+2

Hence,

a 2 + 1 a 2 = 25 2 = 23 , a^2+\frac{1}{a^2}=25-2=\boxed{23},

and we are done.

Jeremy Bansil
Aug 23, 2014

I just ended up with trial and error, ending up with a a as 4.75 4.75 .

4.75 + 1 4.75 = 4.96052631578... 4.75 + \frac{1}{4.75} = 4.96052631578... which estimates to 5 5

4.7 5 2 = 22.5625 4.75^{2} = 22.5625

22.5625 + 1 22.5625 = 22.6068213296... 22.5625 + \frac{1}{22.5625} = 22.6068213296... which estimates to 23 \boxed{23}

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