Simple

$\huge \sqrt 2 \times \sqrt2$

$\huge =(\sqrt 2)^2$

$\huge = 2^{\frac{1}{2} \times 2}$

$\huge = 2^1$

$\huge=\boxed{2}$

√2x√2=√4=2.
Please upvote

x = $\sqrt{2}$ $*\sqrt{2}$

x = $2^{1/2}$ $*2^{1/2}$

x = $(2*2)^{1/2}$

x = $(2^{2})^{1/2}$

x = $2^{2*(1/2)}$

x = $2^{2/2}$

x = $2^{1}$

$\boxed{x = 2}$

$\sqrt{2} \times \sqrt{2}$ can be expressed as \(\sqrt{2}^2} .

Therefore $(\sqrt{2})^2 = 2$

Roots cancel out to provide $\color{#69047E}{\boxed{2}}$ .

2½ × 2½ = (2²)½=2²*½ ( by the law of exponents ) 2¹=2

You should know the very basics. A rational number "q" = $\sqrt{q} \times \sqrt{q}$

Sqrt2 = 1.41421356237

1.41421356237 * 1.41421356237 = 2

Therefore Sqrt2 * Sqrt2 = 2