Simple 5
Probability
Level
2
A bag contains 3 red, 3 green and 3 blue balls. Each ball is put back after it is drawn. What is the probability that in two successive draws, we get a red and a blue ball?
The order that the balls are drawn does not matter.
1/9
2/27
1/27
2/9
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1 solution
Given that each ball should be put back after it is drawn. Hence it is replacement case.
P = 2 ∗ 9 3 ∗ 9 3 = 9 2
We have to multiply probability by 2 because there are two possible wining scenarios "Right Wrong" and "Wrong Right".