Simple Arithmetic Problem Part Two

Algebra Level 3

Find the value of 1 / ( ( 1 × ( 1 + ( 1 ( 1 ) 2 ) 3 ) 4 ) 5 ) ( 1 / ( 1 × ( 1 + ( 1 ( 1 ) 2 ) 3 ) 4 ) 5 ) 1/((1\times (1+(1-(1)2)3)4)5)-(1/(1\times (1+(1-(1)2)3)4)5) .


The answer is 0.6.

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1 solution

Joshua Lowrance
Sep 17, 2019

1 / ( ( 1 × ( 1 + ( 1 ( 1 ) 2 ) 3 ) 4 ) 5 ) ( 1 / ( 1 × ( 1 + ( 1 ( 1 ) 2 ) 3 ) 4 ) 5 ) 1/((1\times(1+(1-(1)2)3)4)5) -(1/(1\times(1+(1-(1)2)3)4)5)

1 ( ( 1 × ( 1 + ( 1 ( 1 ) 2 ) 3 ) 4 ) 5 ) ( 1 1 × ( 1 + ( 1 ( 1 ) 2 ) 3 ) 4 ) 5 ) \large \frac{1}{((1\times(1+(1-(1)2)3)4)5)} - (\frac{1}{1\times(1+(1-(1)2)3)4)}5)

1 ( ( 1 × ( 1 + ( 1 ) 3 ) 4 ) 5 ) 5 ( 1 × ( 1 + ( 1 ) 3 ) 4 ) \large \frac{1}{((1\times(1+(-1)3)4)5)} - \frac{5}{(1\times(1+(-1)3)4)}

1 ( ( 1 × ( 2 ) 4 ) 5 ) 5 ( 1 × ( 2 ) 4 ) \large \frac{1}{((1\times(-2)4)5)} - \frac{5}{(1\times(-2)4)}

1 ( ( 8 ) 5 ) 5 8 \large \frac{1}{((-8)5)} - \frac{5}{-8}

1 40 + 25 40 \large -\frac{1}{40} + \frac{25}{40}

24 40 = 3 5 = 0.6 \large \frac{24}{40} = \frac{3}{5} = 0.6

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