Simple Arithmetic

Level pending

How may solutions are there so that a + b + c + d + e = 20 a + b + c + d + e = 20 where a , b , c , d , e > 1 a, b, c, d, e > -1 ?

For example,
a + b = 3 a + b = 3 have 4 solutions :
a = 0 , b = 3 a = 0, b = 3
a = 1 , b = 2 a = 1, b = 2
a = 2 , b = 1 a = 2, b = 1
a = 3 , b = 0 a = 3, b = 0


The answer is 10626.

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