Given that x = 2 + 2 2 / 3 + 2 1 / 3 , what is
x 3 − 6 x 2 + 6 x ?
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Very clear.
my reply is 2(1+1+1)=6 therefore x=6 given polynomial 6^3 - 6(6^2) + 6(6)=6^3 - 6^3 + 36 = 36 all your steps are inunderstandable and what about mine it is absolutely right
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X = 2 ( 1 + 1 + 1 ) X = 2 3 1 ( 2 3 2 + 2 3 1 + 1 )
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oh sorry i realized when i went to my school. i was in a sleepy mode while i was in brilliant
x − 2 = 2 3 1 ( 2 3 1 + 1 ) Cubing gives us, x 3 − 6 x 2 + 1 2 x − 8 = 6 + 6 × 2 3 1 ( 2 3 1 + 1 ) = 6 + 6 ( x − 2 ) ⇒ x 3 − 6 x 2 + 6 x = 2
We are given that x = 2 + 3 2 + 3 4 . Let x = y + 2 , hence y = 3 2 + 3 4 .
Cube both sides, simplify and substitute again the value of y :
y 3 = ( 3 2 + 3 4 ) 3 y 3 = 2 + 3 3 8 ( 3 2 + 3 4 ) + 4 y 3 = 6 y + 6 y 3 − 6 y − 6 = 0
Finally, since x = y + 2 , we know that y = x − 2 , so:
( x − 2 ) 3 − 6 ( x − 2 ) − 6 = 0 x 3 − 6 x 2 + 1 2 x − 8 − 6 x + 1 2 − 6 = 0 x 3 − 6 x 2 + 6 x = 2
This is exactly the same solution presented by Sanjeet Raria.
x = 2 + 2 2 / 3 + 2 1 / 3
x − 2 = 2 2 / 3 + 2 1 / 3
Cubing both sides:
( x − 2 ) 3 = 6 + 6 × 2 2 / 3 + 6 × 2 1 / 3 = 6 x − 6
( x − 2 ) 3 − 6 x + 8 = 2
x 3 − 6 x 2 + 6 x = 2
: x - 1 = 2^(-1/3)*x So (x-1)^3 = 0.5x^3 x^3 - 3x^2 + 3x - 1 = 0.5x^3 i.e. x^3 - 6x^2 + 6x = 2
Doing it the long way. x 2 = 2 2 + ( 2 3 1 ) 2 + ( 2 3 2 ) 2 + 2 ( 2 ) ( 2 3 2 ) + 2 ( 2 ) ( 2 3 1 ) + 2 ( 2 3 1 ) ( 2 3 2 ) x 2 = 4 + 2 3 2 + 2 3 4 + 4 ( 2 3 2 ) + 4 ( 2 3 1 ) + 2 ( 2 ) x 2 = 8 + 5 ( 2 3 2 ) + 4 ( 2 3 1 ) + 2 3 4 x 2 = 8 + 5 ( 2 3 2 ) + 4 ( 2 3 1 ) + 2 ( 2 3 1 ) x 2 = 8 + 5 ( 2 3 2 ) + 6 ( 2 3 1 ) x 3 = x 2 × x x 3 = [ 8 + 5 ( 2 3 2 ) + 6 ( 2 3 1 ) ] × [ 2 + 2 3 2 + 2 3 1 ) ] x 3 = 3 8 + 2 4 ( 2 3 2 ) + 3 0 ( 2 3 1 )
Thus x 3 − 6 x 2 + 6 x = 2
Using a calculator: I can approximate x quickly as 2 + 1.587 + 1.26 = 4.8476 Plugging into x^3-6x^2+6x I get 113.914 - 140.995 + 29.0856 = 2.0046. I gave 2 as my answer. If it would have been wrong, then I would have gone the other route, performing the algebraic cube.
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X = 2 + 2 3 2 + 2 3 1 X = 2 3 1 ( 2 3 2 + 2 3 1 + 1 ) X = 2 3 1 ( 2 3 2 + 2 3 1 + 2 − 2 + 1 ) X = 2 3 1 ( X − 1 ) C u b i n g b o t h s i d e s X 3 = 2 ( X 3 − 1 − 3 X 2 + 3 X ) X 3 = 2 X 3 − 2 − 6 X 2 + 6 X X 3 − 6 X 2 + 6 X = 2