I f α a n d β a r e t h e r o o t s o f t h e e q u a t i o n x 2 + 3 x − 4 = 0 , t h e n α 1 + β 1 i s e q u a l t o
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
exactly but dang it i pressed the negative sign
Log in to reply
Exactly what I did :p
You can simply use the method of middle term factorization to find out the roots ( 1 , ( − 4 ) ) too!
Why in negative, the answer is wrong?
The roots are 1 and -4.Therefore the required answer is 3/4.
Polynomial → x 2 + 3 x − 4 By vieta’s formula, α + β = a − b = − 3 α ⋅ β = a c = − 4 N o w , α 1 + β 1 = α ⋅ β α + β = − 4 − 3 = 4 3
We know that
x 2 + 3 x − 4 = ( x + 4 ) ( x − 1 )
So the solutions are x = − 4 and x = 1 thus we know − 4 1 + 1 1 = 4 − 1 + 4 = 4 3
Please edit: x-4 ?!!
Problem Loading...
Note Loading...
Set Loading...
Use Vieta's Formula.