Two point charges separated by a distance attract each other with a force of . If one of the charges is increased by and the other is decreased by , then find the new value of the force of interaction at the same distance.
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Force between 2 charges is given by F = 4 π ϵ 0 r 2 q 1 q 2 , where q 1 and q 2 are charges and r is the distance between the charges.
Now, if q 1 is made 1 . 1 q 1 and q 2 is made 0 . 9 q 2 , their product becomes 0 . 9 9 q 1 q 2 .
Hence, the new force between them is 0 . 9 9 times the original value which is 9 . 9 N