If b a = c a ⇒ c = b
Is the statement above true for all real a , b and c ?
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What we usually do:
b a = c a Divide both sides by a ......... [ 1 ] b 1 = c 1 Take reciprocals on both sides........ [ 2 ] b = c
What we does is that we assume that a = 0 in [ 1 ] .
But when we consider all real numbers we also include a = 0 , for which it is not true.
I am sure I attempted this question. Did you delete it and add it again?
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@Mahdi Raza , and @Jeff Giff asked me to edit the options and therefore I deleted that one and rewrote it here.
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b a a c a c − a b a ( c − b ) c = b = c a = a b = 0 = 0 OR a = 0