Let denote the set of all positive rational numbers. If satisfies
evaluate
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Solving the given equation algebraically results in f(x)=sqrt(x) but this does not satisfy the condition of all input giving a rational output, since for example sqrt(2) is irrational, so the function has to be either 1 or 0, but the conditions state that the function must have domain and range greater than zero; it must therefore be a constant function equal to 1.