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A particle of mass 0.1 0.1 kg executes SHM under a force 10 x -10x Newton. If the speed of the particle at the mean position is 6 m s 1 6ms^{-1} , find the amplitude of oscillation in metres.


The answer is 0.6.

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1 solution

BY USING THE FORMULA OF FORCE ACTING ON A SPRING I CALCULATE THE SPRING CONSTANT AND THEN PUT ITS VALUE IN THE FORMULA OF VELOCITY AND PUT X=0 FOR MAXIMUM VELOCITY.

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