Simple hex

Geometry Level 1

Given that ABCDEF is a regular hexagon, and AF = EG, what's the angle measure of A F G \measuredangle AFG in degrees?

Bonus : Generalize a formula, using the ratio of the relative lengths of EG to AF, to determine the angle measure of A F G \measuredangle AFG . For example (don't enter this as the answer for this problem), if EG is 2 times the length of AF, what will be the new angle measure A F G \measuredangle AFG ?


The answer is 135.

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1 solution

Smiti Mittal
Sep 2, 2015

Divide it into angle AFE and EFG- AFE is 120 by (2n-4)90/n for each interior anle of a regular polygon. We know FED is 120, DEG is 90 because it is a square, so sum of angles at a pt is 360 hence FEG must be 150. Since EF an EG are equal, opp angles ar equal too, so by triangle sum property we get 150 + 2EFG is 180 which implies EFG is 15 15 + 120 gives us 135

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