Simple Inequality 1

Algebra Level 4

Given that a , b , c a,b,c are non-negative real numbers satisfying a b c = 2 abc=2 , then a ( b 2 + 1 b ) + b ( c 2 + 1 c ) + c ( a 2 + 1 a ) k a\left(b^2+\dfrac{1}{b}\right)+b\left(c^2+\dfrac{1}{c}\right)+c\left(a^2+\dfrac{1}{a}\right)\ge k for some integer k k . What is k k ?


The answer is 9.

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1 solution

EXPAND AND USE AM-GM

then value of k is 8

Akshay Sharma - 5 years, 6 months ago

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