Integral

Calculus Level 4

What is the (Lebesgue) integral over the reals of the function that takes the value 1 at the rationals and 0 at any other point?

1 not Lebesgue integrable 0 \infty

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1 solution

Bader Naeem
Nov 23, 2016

this is the integral R 1 Q ( x ) d μ ( x ) \int_{\mathbb{R}} 1_{\mathbb{Q}}(x) \, d \mu(x) , where 1 Q ( x ) 1_{\mathbb{Q}}(x) is the indicator function on the reals that evaluates to 1 if x x is rational, and to 0 0 otherwise. μ \mu is Lebesgue measure. Then this integral is simply μ ( Q ) = 0 \mu(\mathbb{Q}) = 0 , since the rationals have zero Lebesgue measure.

FYI You selected the correct answer of 1.

I have updated the answer to 0.

Calvin Lin Staff - 4 years, 6 months ago

Thanks! Sorry for that

Bader Naeem - 4 years, 6 months ago

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