Simple isn't it? #6

A group of friends from BRILLIANT decide to go for a bungee jumping camp. The first one to jump is Adarsh. He jumps from the top of a cliff of height H H . He performs a damped oscillatory motion along the vertical motion. The first time he reaches at the lowest level ,i.e, height of 0 m 0\text{ m} above the ground. Then he goes up to a certain height. Similar type of motion goes on until an equilibrium state is obtained at height h = 51 H 200 h=\frac{51H}{200} .

Find the original length length of rope used for bungee jumping.

The length is of the form a H b \frac{aH}{b} , where a a and b b are positive co-prime integers.

Find a + b a+b

Details and Assumptions

  • Nothing bad happens to Adarsh.
  • Consider Adarsh to be a point sized particle.
This problem is of this set.


The answer is 17.

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1 solution

Alex Wang
Jul 19, 2015

At the lowest level, Adarsh's velocity is 0. Using Conservation of Energy, m g H = 1 2 k ( H L ) 2 mgH = \frac{1}{2} k (H-L)^2

At the final equilibrium state, the net force is 0. Therefore, m g = k ( 149 200 H L ) . mg = k (\frac{149}{200}H - L).

Substitute for mg from the second equation into the first, and k will cancel as well, giving us L = 7 10 H L = \frac{7}{10} H or 17 \boxed{17} as our final answer.

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