Simple log!!

This question can be solved using the three basic properties of logarithmic functions. $log_{a}b^{c} = clog_{a}b$ , $log_{b}x - log_{b}y = log_{b}\frac{x}{y}$ and $log_{a}a = 1$

Applying the second one would make the question $log_{3/2}(3/2)^{3}$ . That would give three.

${ { {\log_{ \frac{3}{2} }27 } - {\log_{ \frac{3}{2} }8 } } = {\log_{ \frac{3}{2} } {\frac{27}{8}} }} = {\underline {3} }$