Simple Logic

Level pending

The least common multiple of two natural numbers a a and b b , is 399 399 . Find the minimum possible sum of the digits of the number a a , given that a > b a>b .

5 7 1 3

Rajasri Ramanolla by Rajasri Ramanolla , 26, India

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2 solutions

Rajasri Ramanolla
Dec 10, 2014

Factorize 399=3×7×19 The possible pairs are (57,7),(21,19),(399,1),(133,3)

The least possible sum is given when a=21 and b=19 And the sum is 2+1= 3.

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399 is divisible by 3 because by simply adding the digits, you arrive at 21, which is divisible by 3. 3 is the sum for the digits of a. Making a digit 111 so that a>b

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