An algebra problem by Viki Zeta

$\frac{\underbrace{4 + \text{ ... } + 4}_{x^2\text{ times}}}{\underbrace{x + \text{ ... } + x}_\text{x times}} - 2 \\ = \frac{4x^2}{x^2} - 2 \\ = 4 - 2 \\ = 2$

Here $\underbrace{4 + \text{ ... } + 4}_{x^2\text{ times}}$ is equal to $4x^2$ as, 4 is added upto $x^2$ times. Like $4 + 4 + 4 = 3 * 4$ , $4+4+4+...+x^2 \text{ times } 4 = 4x^2$ . Similarly for denominator.