Simple Mixture

Algebra Level 2

Kane has a solid box that contains 10 10 litres of alcohol. He drops some amount of water in it, and now the box contains a mixture with an alcohol concentration of 98 % 98\% .

After the mixture of water, if the total volume of mixture in the box can be expressed as a b \frac{a}{b} litres (in lowest term), what is a + b a+b ?


The answer is 549.

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1 solution

Kaizen Cyrus
Feb 4, 2019

An amount of water is added in the 10 10 litres of alcohol. Let x x be the amount of water added.

98 % ( 10 + x ) = 10 98\%(10+x)=10

98 % 98\% of the mixture is 10 10 litres of alcohol. The amount of alcohol never changed since we only added water. That gives us with x = 10 49 x=\frac{10}{49} .

10 + x = 10 + 10 49 = 500 49 10+x=10+\frac{10}{49}=\frac{500}{49}

The total volume of the mixture inside the box is 500 49 \frac{500}{49} litres, giving us the values for a a and b b .

a + b = 500 + 49 = 549 a+b=500+49=\boxed{549}

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