Kane has a solid box that contains litres of alcohol. He drops some amount of water in it, and now the box contains a mixture with an alcohol concentration of .
After the mixture of water, if the total volume of mixture in the box can be expressed as litres (in lowest term), what is ?
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An amount of water is added in the 1 0 litres of alcohol. Let x be the amount of water added.
9 8 % ( 1 0 + x ) = 1 0
9 8 % of the mixture is 1 0 litres of alcohol. The amount of alcohol never changed since we only added water. That gives us with x = 4 9 1 0 .
1 0 + x = 1 0 + 4 9 1 0 = 4 9 5 0 0
The total volume of the mixture inside the box is 4 9 5 0 0 litres, giving us the values for a and b .
a + b = 5 0 0 + 4 9 = 5 4 9