Simple Numbers
Number Theory
Level
2
A sequence of numbers begins 1, 1, 1, 2, 2, 3 and then repeats this pattern forever. What is the sum of 135th, 136th and 137th numbers in the sequence ?
5
7
3
8
6
4
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1 solution
Since the pattern has 6 digits, divide 135 by 6. The quotient is 22 and the remainder is 3. Since 22x6=132, the 132nd number completes the pattern for the 22nd time. So, the 133rd, 134th and 135th numbers are 1s (1,1,1) and the 136th and 137th are 2s (2,2) and their sum is 1+2+2=5. So, the correct answer is 5.