Simple -one

Algebra Level pending

The sum of two numbers is 80 80 , while the sum of the reciprocal of the numbers is 4 75 \frac{4}{75} . Find the smaller of those two numbers.

40 20 30 50

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1 solution

x + y = 80 x + y = 80 1 x + 1 y = 4 75 \frac{1}{x} + \frac{1}{y}= \frac{4}{75} x + y x y = 4 75 \frac{x + y}{xy} = \frac{4}{75} 80 x y = 4 75 \frac{80}{xy} = \frac{4}{75} 4 x y = 6000 4xy = 6000 x y = 1500 xy = 1500 y = 80 x y = 80 - x x ( 80 x ) = 1500 x(80 - x)= 1500 x 2 + 80 x = 1500 -x^{2} + 80x = 1500 x 2 80 x + 1500 = 0 x^{2} - 80x + 1500 = 0

Getting the value for x gives you 30 and 50. Therefore, the answer is 30.

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