The sum of two numbers is
, while the sum of the reciprocal of the numbers is
. Find the smaller of those two numbers.
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x + y = 8 0 x 1 + y 1 = 7 5 4 x y x + y = 7 5 4 x y 8 0 = 7 5 4 4 x y = 6 0 0 0 x y = 1 5 0 0 y = 8 0 − x x ( 8 0 − x ) = 1 5 0 0 − x 2 + 8 0 x = 1 5 0 0 x 2 − 8 0 x + 1 5 0 0 = 0
Getting the value for x gives you 30 and 50. Therefore, the answer is 30.