Rudimental Tetration
If the above number is in the form of for some positve integer , how many positive factors does have (inclusive of and itself)?
Details and Assumptions
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No computational aids is required in solving this problem.
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You may use the fact that is prime.
Image Credit: Wikimedia TetrationConvergence
The answer is 2012.
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1 solution
2 0 1 1 2 0 1 1 2 0 1 2 can be written as ( 2 0 1 1 2 0 1 1 ) 2 0 1 1 2 0 1 1
Therefore x= 2 0 1 1 2 0 1 1 As 2011 is a prime number total number of factor is 2012