A circular loop has resistance 12 ohm.Tow points and are selected on the loop, so that the loop will be divided into two parts in the ratio 1 : 3. Electric cell of 9 volt is applied across and . Calculate the total current across the loop.
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Resistances of two sections of the loop are 3 and 9, combined resistance:
R 1 = 3 Ω 1 + 9 Ω 1 ⇒ R = 4 9 Ω ,
I = R V = 9 / 4 9 = 4 A