Simple. (Problem $5$ )

Algebra Level pending

$\frac{x + 2}{x}$ $= x$

Find the positive value of $x + 1$ .

1 solution

Yajat Shamji
Jul 9, 2020

$\frac{x + 2}{x}$ $= x$

$x + 2 = x^2$

$x^2 - (x + 2) = 0$

$x^2 - -x - 2 = 0$

$x^2 + x - 2 = 0$

$(x + 2)(x - 1) = 0$

$x = -2, 1$

$x + 1 = -1, 2$

Since we're asked for the positive value of $x + 1$ , $x + 1 = \fbox{2}$ .

$\color{#D61F06}Error! \ Error! \ Error \ in \ step \ 2!$

$Should \ be \ x^2-(x+2)=0 \ (You \ forgot \ the \ parentheses!)$

Lâm Lê - 9 months, 1 week ago

Whoops! @Lin Le

Yajat Shamji - 9 months, 1 week ago