Simple problem (I.Q test)

Count the intersections and get $\boxed{4}$

$3^2=9$

$1^2=1$

$2^2=4$

let's solve the sum using BODMAS

In the first figure 3 lines are horizontal and 3 lines are vertical

then let's check which operation makes it = 9:

3+3= 6

3-3=0

3/3 = 1

3x3=9

so multiplication makes it true

even in the second figure:

1 x 1 = 1

1/1=1

1+1=2

1-1=0

but to make the first equation true we keep it multiplication

so in the next figure :

2 x 2 = 4

the problem can be solved using line intersections:

the first diagram has 9 intersections = 9

the second one has 1 intersection = 1

and the last one has four intersections = 4

and exponents too:

1st one has three(3) vertical/horizontal lines so

3 squared or 3 x 3 = 9 so 9

2nd one has one(1) vertical/horizontal lines so

1 squared or 1 x 31 = 1 so 1

3rd one has two(2) vertical/horizontal lines so

2 squared or 2 x 2 = 4

Write how many times the lines cross each other.