There is a number lying between 100 and 199 and having 2 at one's place, sum of the digits of numbers is greater then 3 but less then 9 (but not equal to 3 or 9) , if the number is divisible by three find out that number
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If the number is between 100-199 and the one's place is a two, the number is '1x2', where x is a integer for the ten's place.
In order to have a number divisible by three, the digit sum must also be divisible by three. Therefore 1+x+2=(3,6,9) since the problem states that the sum isn't 3 or 9, the digit sum must be six.
1+x+2=6
X=3
The answer is 132