Simple Problem on quardritic polynomials

Algebra Level 1

Let A be a possitive natural number and B be the successor of A , if value of A×B is 56 find out the value of A+B


The answer is 15.

Aman Sharma by Aman Sharma , 25, India

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3 solutions

Ritam Baidya
Dec 3, 2014

SOLVING the quad. eq. A*2+A-56 we get A=7 so B=(7+1)=8 and hence A+B=(7+8)=15

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Brett Hartley
Aug 18, 2014

A × B = 56 A \times B=56 and A + B = ? A+B=? and A = B − 1 A=B-1 so A × B = A 2 + A A \times B=A^{2}+A therefore 56 = A 2 + A 56=A^{2}+A , solving the quadratic equation gives A = 7 A=7 thus using B = A + 1 B=A+1 , B = 8 B=8 so A + B = 15 \boxed{A+B=15}

0 Helpful 1 Interesting 0 Brilliant 1 Confused
Eagle Vinesh
Aug 14, 2014

A X B = 56 MEANS 7 X 8 = 56 S0 A + B = 7+8 = 15

0 Helpful 0 Interesting 1 Brilliant 0 Confused

So you solved it by triel and error right

Aman Sharma - 6 years, 10 months ago

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trial, positive and quadratic and this question is best solved by trial and error as it is fairly easy to see the answer without much effort

Brett Hartley - 6 years, 9 months ago

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