Simple Quadratic

Algebra Level 2

What is the largest possible value for x x such that 2 x 2 − 47 x + 221 = 0 2x^2-47x+221 = 0

13 2 \frac{13}2 15 2 \frac{15}2 16 17

A P by A P , 26, USA

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2 solutions

A P
Feb 12, 2016

Using the quadratic Formula, we have 47 + 2209 − 1768 4 \frac{47 + \sqrt{2209 -1768}}{4} . Simplifying we have 68 4 \frac{68}{4} which equals 17.

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Hello I use method of Plug In Answer Choice. It hear it is very OP.

Jon Sy - 5 years, 1 month ago

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I have spent 3 years meditating upon this quadratic and am now convinced it is the meaning of life. Its exquisite complexity feeds the mind eternally and its solution so crisp and aardvark-like it is a delight to the senses. I have decided to spend the rest of my life with this quadratic, in perfect happiness and I have begun a new religion surrounding it. Anyone may join. Thenk.

Percy 17 hax0r - 5 years ago
Kay Xspre
Feb 13, 2016

Factorization gives ( 2 x − 13 ) ( x − 17 ) = 0 ⇒ x = 13 2 , 17 (2x-13)(x-17)=0 \Rightarrow x = \frac{13}{2}, 17

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