Simple "Sum" of Pascal

Level pending
//This is PseudoCode
a := 1;
b := 2;
c := a + b;
sum := 0;
for i := 1 to 3 do
begin
    inc(a); inc(b);
    sum := sum + a + b;
    sum := sum + c;
end;
writeln(sum);

What is the last result of sum ?


The answer is 36.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Jansen Wu
Feb 7, 2014

a = 1 , b = 2 , c = a + b = 3; when i = 1 : inc(a) = a + 1 = 2; inc(b) = b + 1 = 3; sum = 0 + 2 + 3 = 5; sum = 5 + c = 5 + 3 = 8;

a = 2 , b = 3 , c = a + b = 5; when i = 2 : inc(a) = a + 1 = 3; inc(b) = b + 1 = 4; sum = 8 + 3 + 4 = 15; sum = 15 + c = 15 + 5 = 20;

a = 3 , b = 4 , c = a + b = 3 + 4 = 7; when i = 3 : inc(a) = a + 1 = 4; inc(b) = b + 1 = 5; sum = 20 + 4 + 5 = 29; sum = 29 + c = 29 + 7 = 36;

the looping has stopped and the last result of sum is 36 .

Variable C never change actually

Chalvin Rmc - 7 years, 4 months ago

Log in to reply

oo..i see....the answer is 30

Jansen Wu - 7 years, 4 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...