sin θ + sin 2 θ = 1
If the above equation is true, find the value of the expression below
cos 2 θ + cos 4 θ .
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Same solution
also try this problem of trigonometry triangles
Given
sin θ + sin 2 θ =1 ---->(1)
Identity I ⇒ sin 2 θ + cos 2 θ =1 ---->(2)
By comparing (1)=(2)
We get sin θ = cos 2 θ
If sin θ = cos 2 θ , then sin 2 θ = cos 4 θ
Therefore cos 2 θ + cos 4 θ = sin θ + sin 2 θ
⇒ cos 2 θ + cos 4 θ = 1
This is the same as the first.
We know sin^2 theta+cos^2 theta=1 It is given, sin theta+sin^2 theta=1 so sin theta=cos^2 theta to find cos^2 theta+cos^4 theta substitute sin theta in place of cos^2 theta and sin^2 theta in place of cos^4 theta we get sin theta+sin^2 theta=? value is already given as 1 ans is 1
Ans: 1 cos²θ = 1 - sin²θ = 1 - (1 - sin θ) = sin θ cos²θ + cos⁴θ = cos²θ(1 + cos²θ) = sin θ(1 + sin θ) = sin θ + sin²θ = sin θ + (1 - sin θ) = 1
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S i n θ = 1 − s i n 2 θ
S i n θ = c o s 2 θ
So
c o s 4 θ = s i n 2 θ
c o s 2 θ + c o s 4 θ = s i n θ + s i n 2 θ = 1
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