A calculus problem by Hemanth Koundinya

Calculus Level 1

Which of the following is an antiderivative of sin x \sin x ?

tan x -\tan x cos x -\cos x sin x -\sin x csc x -\csc x

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1 solution

Lu Chee Ket
Jan 24, 2015

y = Cos x

y + d y = Cos (x + d x)

d y = Cos (x + d x) - Cos x

d y = - 2 Sin (x + d x/ 2) Sin (d x/ 2)

d y/ d x = - Sin (x + d x/ 2) [Sin (d x/ 2)]/ (d x/ 2)

d y/ d x = - Sin x as d x --> 0

Integrate - Sin x d x = Cos x + k

Therefore, Integrate Sin x d x = - Cos x + constant.

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