3 4 3 × 3 4 3 + 3 4 3 × 1 1 3 + 1 1 3 × 1 1 3 3 4 3 × 3 4 3 × 3 4 3 − 1 1 3 × 1 1 3 × 1 1 3 = ?
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same solution.. +1 :)
Nice use of colors, however, note that on the second line and third line y 2 is written as y 2
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Thanks.. I knew I forgot something in one of my solutions here it is... But it's very difficult to keep track of so many solutions... :-)
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I know. These few days, I have been seeing the same two people dump out so many solutions
Nice solution.. +1 :)
suppose, 343=a and 113=b
so,it stands as..=a^3-b^3/(a^2 + ab + b^2)
=(a-b)(a^2+ ab +b^2) /(a^2 + ab + b^2)
=a-b
=343-113=230
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Relevant wiki: Algebraic Identities
Substitute x = 3 4 3 , y = 1 1 3 followed by using a 3 − b 3 = ( a − b ) ( a 2 + a b + b 2 )
A = 3 4 3 × 3 4 3 + 1 1 3 × 3 4 3 + 1 1 3 × 1 1 3 3 4 3 × 3 4 3 × 3 4 3 − 1 1 3 × 1 1 3 × 1 1 3
= x 2 + y x + y 2 x 3 − y 3
= x 2 + y x + y 2 ( x − y ) ( x 2 + y x + y 2 )
= x − y = 3 4 3 − 1 1 3 = 2 3 0