If , then what is the number of digits of ?
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Here, 2²⁰²¹×5^²⁰²⁰×3² =2×{(2×5)²⁰²⁰}×9 =18×(10²⁰²⁰) Now, It's quite known to all that if M=10^k then M has exactly (k+1) digits. So , in this case , we can say that 10^2020 has 2021 digits......and when we multiply it by 18 ,1 digit increases... So , A has 2022 digits.......