A circle is inscribed in a triangle of sides 3, 4 and 5 cm. Find it's radius
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r = P 2 A where A = a r e a , P = p e r i m e t e r
r = 3 + 4 + 5 2 ( 2 1 ) ( 3 ) ( 4 ) = 1 2 1 2 = 1
Note that the triangle is a right triangle.
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Using the formula, R = S e m i p e r i m e t e r A r e a o f t r i a n g l e ,
We get, Area of triangle as 6 c m 2 and Semi-Perimeter as 6 c m
R= 6 6 = 1