What is the sum of the digits of the product of 3 6 × 2 4 × 5 7 ?
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Because of the test choices given, it is enough to observe that the number is divisible by 9 , hence the sum of the digits is also divisible by 9 , and 1 8 was the only choice divisible by 9 .
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n = 1 ∑ 4 ( n + 1 ) it means that first, we will start with replacing n. n= 1. start with 1, 1+1=2, 2+1=3,3+1=4,4+1=5. end in 4.now add these values, 2+3+4+5 = 14 n = 1 ∑ 4 ( n + 1 ) = 1 4 it is used to add numbers in sequence
On rearranging,
3
6
×
2
4
×
5
7
=
(
2
×
3
×
5
)
4
×
(
3
×
5
)
2
×
5
Solving,
⇒
3
6
×
2
4
×
5
7
=
(
3
0
)
4
×
(
1
5
)
2
×
5
⇒
3
6
×
2
4
×
5
7
=
(
8
1
0
0
0
0
)
×
(
2
2
5
)
×
5
⇒
3
6
×
2
4
×
5
7
=
(
4
0
5
0
0
0
0
)
×
(
2
2
5
)
⇒
3
6
×
2
4
×
5
7
=
9
1
1
2
5
0
0
0
0
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3 6 ∗ 2 4 ∗ 5 7 = ( 3 2 ) 3 ∗ 1 0 4 ∗ 5 3 = 9 3 ∗ 1 0 4 ∗ 5 3 = 9 3 ∗ 1 0 4 ∗ 5 3 = 4 5 3 ∗ 1 0 4 = 9 1 1 2 5 0 0 0 0 , ∑ = 1 8 1 8