simply numbered !!!
Algebra
Level
pending
The number of integral values of 'a' for which ax²-(4-2a) x-8<0 for exactly three integral values of x is ??
The answer is 2.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
ax²-(4-2a)x-8<0 (x-4÷a)(x+2)<0 x belongs to (-2,4÷a) According to the question a is having some itegral values for which x is having exactly 3 integral values If a=1 thenx will have -1,0,1,2,3 as ans but we need only 3 integral values of x; if a=2 then x will belong to -1,0,-1 which is correct ; and when a=3 x€(-2,4÷3)={-1,0,1} and if a=4 x={-1,0} only two integral values which is incorrect So, the possibility of itegral values of x are -1,0,1 for diff values of a, where a€{2,3} and ans= 2